Questions
- Answer: They are used to display status in things like alarm control panels, keyboards, monitors, and printers.
- Answer: Period is the time it takes for a signal to repeat.
- Answer: Frequency is the rate at which the light blinks on/off.
- Answer: Duty cycle is a measure of how much time a repeating signal stays on (high) durings its period.
- Answer: The period, frequency, duty cycle, and the number of times it blinks are ways to manipulate a light blinking.
Exercises
- Answer: Change sleep(500) to sleep(250)
- Answer: Make the first sleep value (for pin14.write_digital(1)) higher than the second sleep value.
- Answer: sleep values of around 5 will achieve this.
- Answer: (0)
- Answer: You can use this loop to measure out the number of times a light blinks.
- Answer:
T = tHIGH + tLOW
1 = .25 s + tLOW
tLOW = .75 s - Answer:
F = 1 / T
F = 1 / .75 s
F = 1 â…“ Hz - Answer:
%DC = [ tHIGH / (tHIGH + tLOW) ] x 100%
= [ 500 ms / (500 ms + 500 ms) ] x 100%
= 0.5 x 100%
= 50% - Answer:
%DC = [ tHIGH / (tHIGH + tLOW) ] x 100%
30 = [ 300 ms / (300 ms + tLOW) ] x 100%
0.3 = (300 ms / 300 ms + tLOW)
0.3 x (300 ms + tLOW) = 300 ms
90 ms + .3(tLOW) = 300 ms
0.3(tLOW) = 210 ms
tLOW = 700 ms
Period = tHIGH + tLOW = 300 ms + 700 ms = 1000 ms
Projects
- Solution
from microbit import* for n in range(0, 20): pin14.write_digital(1) sleep(750) pin14.write_digital(0) sleep(500)
- Solution
from microbit import* time = 1000 scale = .5 for t in range (2500,0,-100): pin14.write_digital(1) sleep(time) pin14.write_digital(0) sleep(time) if t <= 1500: scale = .75 elif t > 1500: scale = 1 time = time * scale