Solutions

Questions

  1. Answer: They are used to display status in things like alarm control panels, keyboards, monitors, and printers.
  2. Answer: Period is the time it takes for a signal to repeat.
  3. Answer: Frequency is the rate at which the light blinks on/off.
  4. Answer: Duty cycle is a measure of how much time a repeating signal stays on (high) durings its period.
  5. Answer: The period, frequency, duty cycle, and the number of times it blinks are ways to manipulate a light blinking.

Exercises

  1. Answer: Change sleep(500) to sleep(250)
  2. Answer: Make the first sleep value (for pin14.write_digital(1)) higher than the second sleep value.
  3. Answer: sleep values of around 5 will achieve this.
  4. Answer: (0)
  5. Answer: You can use this loop to measure out the number of times a light blinks.
  6. Answer:   
    T = tHIGH + tLOW
    1 = .25 s + tLOW
    tLOW = .75 s
  7. Answer:    
    F = 1 / T
    F = 1 / .75 s
    F = 1 â…“ Hz
  8. Answer:
    %DC = [ tHIGH / (tHIGH + tLOW) ] x 100%
    = [ 500 ms / (500 ms + 500 ms) ] x 100%
     =  0.5 x 100%
     = 50%
  9. Answer:     
    %DC = [ tHIGH / (tHIGH + tLOW) ] x 100%
    30 = [ 300 ms / (300 ms + tLOW) ] x 100%
    0.3 =  (300 ms / 300 ms + tLOW)
    0.3 x (300 ms + tLOW) = 300 ms
    90 ms + .3(tLOW) = 300 ms
    0.3(tLOW) = 210 ms
    tLOW = 700 ms
    Period = tHIGH + tLOW = 300 ms + 700 ms = 1000 ms

Projects

  1. Solution
from microbit import*
        
for n in range(0, 20):
      pin14.write_digital(1)
      sleep(750)
      pin14.write_digital(0)
      sleep(500)

 

  1. Solution
from microbit import*

time = 1000
scale = .5

for t in range (2500,0,-100):
    
    pin14.write_digital(1)
    sleep(time)
    pin14.write_digital(0)
    sleep(time)

    if t <= 1500:
        scale = .75
    elif t > 1500:
        scale = 1
        
         time = time * scale