Strengthen Your Cipher with Substitution

At the end of the Cybersecurity: Encryption Intro tutorial, there’s a Your Turn in the Substitution Ciphers page where you created a scrambled_alphabet_cipher script.  This kind of function is a much better defense against brute force attacks.  Instead of testing 93 possible shifts, a brute force attack would have to try decrypting with 26! permutations of the alphabet.  The term 26! is pronounced 26 factorial.  

3! = 3 * 2 * 1 = 6
4! = 4 * 3 * 2 * 1 = 24
5! = 5 * 4 * 3 * 2 * 1 = 120

26! = 403,291,461,126,605,635,584,000,000

Wow!  That would be a lot of rearrangements of the alphabet for a brute force algorithm to crack.  Also, who would try to look at all those combinations to find the intelligible text?

Example script: scrambled_alphabet_cipher

  • Enter, save, and flash scrambled_alphabet_cipher into a micro:bit.
# scrambled_alphabet_cipher

from microbit import *

# Scrambled alphabet cipher.
def scramble(text, encrypt):
    alpha  = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    crypta = "PTQGMKCRSVEXADZBJFOWYNIHLU"
    result = ""
    
    if encrypt is False:
        temp = alpha
        alpha = crypta
        crypta = temp

    for letter in text:
        letter = letter.upper()
        index = alpha.find(letter)
        result = result + crypta[index]

    return result

# The script starts executing statements from here.

sleep(1000)

print("Set your keyboard to CAPS LOCK.")
print()

while True:
    text = input("Enter a CAPS LOCK string: ")
    
    result = scramble(text, True)

    print("scrambled result =", result)
    
    result =  scramble(result, False)
    
    print("unscrambled result =", result)

 

  • Click the Open Serial button.
  • Type HAPPY into the terminal.
  • Verify that the scrambled result is RPBBL.  That’s the encrypted result.
  • Verify that the unscrambled, decrypted result is HAPPY.